[2024-06-24更新,250問] 無料Oracle 1z0-071試験問題集、1z0-071予想試験(ページ 16)

1z0-071 試験問題 71

次のコマンドを使用してテーブルを作成します。
CREATE TABLE rate_list (rate NUMBER(6,2));
ステートメントの実行について正しいのはどれですか?

A. INSERT INTO rate_list VALUES (87654. 556) は、値を 87654.6 として挿入します。

B. INSERT INTO rate_list VALUES (0.551) は、値を .55 として挿入します。

C. INSERT INTO rate_list VALUES (-.9) は、値を -.9 として挿入します。

D. INSERT INTO rate_list VALUES (0.999) ではエラーが発生します。

E. INSERT INTO rate_list VALUES (-99.99) は、値を 99.99 として挿入します。

F. INSERT INTO rate_list VALUES (-10) はエラーを生成します。

1z0-071 試験問題 72

Evaluate the following SQL statement:

Which statement is true regarding the outcome of the above query?

A. It executes successfully and displays rows in the descending order of PROMO_CATEGORY.

B. It executes successfully but ignores the ORDER BY clause because it is not located at the end of the compound statement.

C. It produces an error because positional notation cannot be used in the ORDER BY clause with SET operators.

D. It produces an error because the ORDER BY clause should appear only at the end of a compound query-that is, with the last SELECT statement.

1z0-071 試験問題 73

Which three privileges can be restricted to a subset of columns in a table? (Choose three.)

A. DELETE

B. ALTER

C. SELECT

D. INSERT

E. REFERENCES

F. INDEX

G. UPDATE

1z0-071 試験問題 74

Which statement is true regarding the INTERSECToperator?

A. The names of columns in all SELECTstatements must be identical.

B. It ignores NULLvalues.

C. Reversing the order of the intersected tables alters the result.

D. The number of columns and data types must be identical for all SELECTstatements in the query.

1z0-071 試験問題 75

View the Exhibit and examine the description of the EMPLOYEES table.

You want to calculate the total remuneration for each employee. Total remuneration is the sum of the annual salary and the percentage commission earned for a year. Only a few employees earn commission.
Which SQL statement would you execute to get the desired output?

A. SELECT first_name, salary, salary*12+salary*commission_pct "Total"FROM EMPLOYEES;

B. SELECT first_name, salary (salary + NVL (commission_pct, 0)*salary)*12 "Total"FROM EMPLOYEES;

C. SELECT first_name, salary, salary*12 + NVL(salary,0)*commission_pct, "Total"FROM EMPLOYEES;

D. SELECT first_name, salary, salary*12+(salary*NVL2 (commission_pct,
salary,salary+commission_pct))"Total"FROM EMPLOYEES;

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1z0-071 試験問題 71

1z0-071 試験問題 72

1z0-071 試験問題 73

1z0-071 試験問題 74

1z0-071 試験問題 75

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